Ncert Solution Of Class 10th Hindi Sanchayan Map
20.02.2021
NCERT Solutions for Class 10 Hindi Sanchayan Chapter 3 Topi Shukla PDF
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Answer: Three, these are n-pentane, iso-pentane and neo-pentane. Question 2 What Ncert Solution Of Class 10th Hindi Sanchayan Map are the two properties of carbon which lead to the huge number of carbon compounds we see around us? Answer: i Tetravalency ii Catenation. Question 3 What will be the formula and Ncert Solution Of Class 10th Hindi Sanchayan Map electron dot structure of cyclopentane?
Answer: The molecular formula of cyclopentane is C 5 H The electron dot structure of cyclopentane is given on the next page. Structural isomers for bromopentane: There are three structural isomers for bromopentane depending on the position of Br at carbon 1, 2, 3.
Positions 4 and 5 are same as 1, 2. Question 5 How would you name Ncert Solution Of Class 10th Hindi Sanchayan Map the following compounds? Answer: i Bromoethane ii Methanal iii 1 � Hexyne. Question 1 Why is the conversion of ethanol to ethanoic acid an oxidation reaction?
Answer: Conversion of ethanol into ethanoic acid is an oxidation reaction because addition of oxygen to a substance is called oxidation. Here, oxygen is added to ethanol by oxidising agent like alkaline potassium permanganate or acidified potassium dichromate Ncert Solution Of Class 10th Hindi Sanchayan Map and it is converted into acid.
Question 2 A mixture of oxygen and ethyne is burnt for welding. Can you tell why a mixture of ethyne and air is not used? Answer: Ncert Solution Of Class 10th Hindi Sanchayan Map Ncert Solution Of Class 10th Hindi Sanchayan Map A mixture of ethyne and air is not used for welding because burning of ethyne in air produces a sooty flame due to incomplete combustion, which is not enough to melt Ncert Solution Of Class 10th Hindi Sanchayan Map metals for welding.
Question 1 How would you distinguish experimentally between an alcohol and a carboxylic acid? Answer: Differences between alcohol and carboxylic acid. Question 2 What are oxidising agents? Answer: Oxidising Ncert Solution Of Class 10th Hindi Sanchayan Map agents are the substances which give oxygen to another substances or which remove hydrogen from a substance. For example, acidic K 2 Cr 2 O 7 is an oxidising agent, that converts Ncert Solution Of Class 10th Hindi Sanchayan Map oxidises ethanol into ethanoic acid.
Question 1 Would you be able to check if water is hard by using a detergent? Answer: No, because detergents can lather well even in hard water. They do not form insoluble calcium or magnesium salts scum. On reacting with the calcium ions and magnesium ions present in the hard water. Question 2 People use a variety of methods Ncert Solution Of Class 10th Hindi Sanchayan Map to wash clothes. Why is agitation necessary to get clean clothes?
Answer: It is necessary to agitate to get clean clothes because the soap micelles which entrap oily or greasy particles on Ncert Solution Of Class 10th Hindi Sanchayan Map the surface of dirty cloth have to be removed from its surface. When the cloth wetted in soap solution is agitated or beaten, the micelles containing oily or greasy dirt get removed from the surface of dirty cloth and go into water and the dirty cloth gets cleaned. Question 1 Ethane, with the molecular formula C 2 H 6 has a 6 covalent bonds b 7 covalent bonds c 8 covalent bonds d 9 covalent bonds Answer: b 7 covalent bonds.
Question 2 Butanone is a four-carbon compound with the functional group a carboxylic acid Ncert Solution Of Class 10th Hindi Sanchayan Map b aldehyde c ketone d alcohol Answer: c Ketone. Question 3 While cooking, if the bottom of the vessel is getting blackened on the outside, it means that a the food is Ncert Solution Of Class 10th Hindi Sanchayan Map not cooked completely. Answer: b The fuel is not burning completely. Question 4 Explain the nature of the covalent bond using the bond formation in CH 3 Cl.
Answer: Covalent bond is Ncert Solution Of Class 10th Hindi Sanchayan Map formed by sharing of electrons so that the combining atoms complete their outermost shell. Chlorine completes its outer shell by sharing its one out of seven electrons with one electron of carbon atom. Thus carbon atom shares all its four electrons with three hydrogen atoms and one of chlorine atom and completes its outermost Ncert Solutions For Class 10th Hindi Sanchayan Number shell and single covalent bonds are formed in CH 3 Ncert Solution Of Class 10th Hindi Sanchayan Map Ncert Solution Of Class 10th Hindi Sanchayan Map Cl.
Question 5 Draw the electron dot structures for a ethanoic acid b propanone c H 2 S d F 2. Question 6 What is a homologous series? Explain with an example. Answer: Ncert Solution Of Class 10th Hindi Sanchayan Map Homologous series : A homologous series is a group of organic compounds having similar structures and similar chemical properties in which the successive compounds differ by -CH 2 group. Characteristics of homologous Ncert Solution Of Class 10th Hindi Sanchayan Map series : i All members of a homologous series can be represented by the same general formula.
Question 7 How can ethanol and ethanoic acid he differentiated on the basis of their Ncert Solution Of Class 10th Hindi Sanchayan Map Ncert Solution Of Class 10th Hindi Sanchayan Map physical and chemical properties? Answer: Difference on the basis of physical properties.
Question 8 Why does micelle formation take place when soap is added to water? Will a micell be formed in Ncert Solution Of Class 10th Hindi Sanchayan Map other solvents such as ethanol also? Answer: Micelle formation takes place when soap is added to water because the hydrocarbon chains of soap molecules are hydrophobic water repelling which are insoluble in Ncert Solution Of Class 10th Hindi Sanchayan Map Ncert Solution Of Class 10th Hindi Sanchayan Map water, but the ionic ends of soap molecules are hydrophilic water attracting and hence soluble in water. Such micelle formation will not be possible in other solvents like ethanol in which sodium Ncert Solution Of Class 10th Hindi Sanchayan Map Ncert Solution Of Class 10th Hindi Sanchayan Map salt of fatty acids do not dissolve.
Question 9 Why are carbon and its compounds used as fuels for most applications? Answer: Carbon and its compounds give a large amount of heat per unit weight and are therefore, used as fuels for most applications. Question 10 Explain the formation of scum when hard water is treated with soap.
Answer: Hard water contains salts of calcium and magnesium. Calcium and magnesium on reacting with soap form insoluble precipitate called scum. The scum formation lessens the cleansing property of soaps in hard water. Question 11 What change will Ncert Ncert Solutions Class 10th Hindi Sanchayan No Solution Of Class 10th Hindi Sanchayan Map Map Class Sanchayan Solution Ncert Of Hindi 10th Ncert Solution Of Class 10th Hindi Sanchayan Map you observe if you test soap with litmus paper red and blue? Answer: Red litmus will turn blue because soap is alkaline in nature. Blue litmus remains blue in soap solution.
Question Ncert Solution Of Class 10th Hindi Sanchayan Map Ncert Solution Of Class 10th Hindi Sanchayan Map Ncert Solution Of Class 10th Hindi Sanchayan Map Ncert Solution Of Class 10th Hindi Sanchayan Map 12 What is hydrogenation? What is its industrial application? Answer: The addition of hydrogen to an unsaturated hydrocarbon to obtain a saturated hydro-carbon is called hydrogenation.
The process of hydrogenation takes place in the presence of nickel Ni or palladium Pd metals as catalyst. Application : The process of hydrogenation has an important industrial application.
It is used to prepare vegetable ghee or vanaspati Ncert Solution Of Class 10th Hindi Sanchayan Map 10th Sanchayan Map Hindi Ncert Class Solution Of Ncert Solution Of Class 10th Hindi Sanchayan Map ghee from vegetable oils. So addition reaction take place only in C 3 H 6 and C 2 H 2. Question 14 Give a test that can be used to differentiate chemically Ncert Solution Of Class 10th Hindi Sanchayan Map between butter and cooking oil. Answer: Butter is a saturated carbon compound while cooking oil is an unsaturated carbon compound. An unsaturated compound decolourises bromine water, while a saturated compound cannot decolourise it.
So we can distinguish chemically between a cooking oil and butter by the bromine water. Add bromine water to a little of cooking oil and butter taken in separate test-tubes. Question 15 Explain the mechanism of the cleaning action of soaps. OR Explain the cleansing action of soaps. In this way the soap micelle entraps the oily or greasy particles by using its Ncert Solution Of Class 10th Hindi Sanchayan Map hydrocarbon ends. The ionic ends of the soap molecules in the micelles, however, remain attached to water.
When the dirty cloth is agitated in soap solution, the oily and greasy particles present Ncert Solution Of Class 10th Hindi Sanchayan Map Ncert Solution Of Class 10th Hindi Sanchayan Map Ncert Solution Of Class 10th Hindi Sanchayan Map Ncert Solution Of Class 10th Hindi Sanchayan Map Ncert Solution Of Class 10th Hindi Sanchayan Map on its surface and entrapped by soap micelles get dispersed in water due to which the soap water becomes dirty but the cloth gets cleaned. The cloth is cleaned thoroughly by rinsing in clean water a number of times. Carbon compounds: Covalent bonding in carbon compounds, Versatile nature of carbon, Homologous series, Nomenclature of carbon compounds containing functional groups, halogens, alcohol, ketones, aldehydes, alkanes, and alkynes , difference between saturated hydrocarbons and unsaturated hydrocarbons.
Chemical properties of carbon compounds combustion, oxidation, addition and substitution reaction. Ethanol only properties and uses , Ethanoic acid only properties and uses , soaps and detergents.
Formulae Handbook for Class 10 Maths and Science. Question 2 What would be the electron dot structure of a molecule of sulphur, which is made up of eight atoms of sulphur? Hint � The eight atoms of sulphur are joined together in the form of a ring.
Question 3 How many structural isomers can you Ncert Solution For Class 10th Hindi Sanchayan Fun draw for pentane? Solution: We can Ncert Solution Of Class 10th Hindi Sanchayan Map draw 3 structural isomers for pentane. Question 4 What are the two properties of carbon that lead to the huge number of carbon compounds we see around us?
Solution: Due to its Ncert Solution Of Class 10th Hindi Sanchayan Map Ncert Solution Of Class 10th Hindi Sanchayan Map large valency, carbon atoms can form covalent bonds with a number of carbon atoms as well as with a large number of other atoms such as hydrogen, oxygen, nitrogen, sulphur, chlorine and many more atoms. This leads to the formation of a large number of organic compounds. Question 5 What will be the formula and electron dot structure of Cyclopentane?
Question 6 Draw the Ncert Solution Of Class 10th Hindi Sanchayan Map structures for the following compounds. Ethanoic acid ii. Bromopentane iii. Butanone iv. Hexanal Solution:. Question 7 How would you name the following compounds?
Solution: i. Ethyl bromide ii. Formaldehyde iii. Question 8 Why is the conversion of ethanol to Ethanoic acid an oxidation reaction? Solution: The conversion of ethanol into ethanoic acid is called an oxidation reaction because oxygen is added to it Ncert Solution Of Class 10th Hindi Sanchayan Map Ncert Solution Of Class 10th Hindi Sanchayan Map during this conversion. Question 9 A mixture of oxygen and ethyne is burnt for welding. Solution: When a mixture of oxygen and ethyne is burnt, it burns completely producing a blue flame.Ncert Solution Of Class 10th Hindi Sanchayan Map
This blue flame is extremely hot which produced a very high temperature which is used for welding metals. But the mixture of ethyne and air is not used for welding purposes because Ncert Solution Of Class 10th Hindi Sanchayan Map burning of ethyne in air produces a sooty flame, which is not enough to melt metals for welding.
Question 10 What are oxidizing agents? Solution: Oxidizing agents are the substances that gain Map Hindi Of Class Sanchayan Solution Ncert 10th electrons in an redox reaction and whose oxidation number is reduced. Question 11 Explain the nature of the covalent bond using the bond formation of CH 3 Cl.
Solution: CH 3 Cl Ncert Solution Of Class 10th Hindi Sanchayan Map methyl chloride is made up of one carbon atom, three hydrogen atoms and one chlorine atom. Carbon atom has 4 valence electrons, each hydrogen atom has one valence electron, and a chlorine atom has 7 valence electrons. Carbon atom shares its four valence electrons with three hydrogen atoms and 1 chlorine atom to form methyl chloride as follows: From the above reaction, in the dot structure of methyl chloride CH 3 Cl there are four pairs of shared electrons between carbon and other atoms.
Each pair of shared electrons constitutes one single covalent bond. So, Ncert Solution Of Class 10th Hindi Sanchayan Map Ncert Solution Of Class 10th Hindi Sanchayan Map methyl chloride has four single covalent bonds. Question 12 Draw the electron dot structures for- Solution:. Question 13 What is a homologous series? Solution: Homologous series is a series of compounds with Ncert Solution Of Class 10th Hindi Sanchayan Map Ncert Solution Of Class 10th Hindi Sanchayan Map a similar general formula, possessing similar chemical properties due to the presence of the same functional group, and shows a gradation in physical properties as a result of increase in molecular size Ncert Solution Of Class 10th Hindi Sanchayan Map and mass.
For example, methane has a lower boiling point than ethane since it has more intermolecular forces with neighbouring molecules. This is because of the increase in the number of atoms Ncert Solution Of Class 10th Hindi Sanchayan Map making up the molecule. Question 14 How can ethanol and Ethanoic acid be differentiated on the basis of their physical and chemical properties? Solution: i Ethanol has a pleasant smell whereas ethanoic acid has the smell of vinegar.
Question 15 Why does micelle formation take place when soap is added to water? Will a micelle be formed in other solvents such as ethanol also? Solution: Micelle formation takes place when soap is added to water. This is because when soap is added to water in which dirty clothes are soaked, the two parts of the soap Ncert Solution Of Class 10th Hindi Sanchayan Map molecule dissolves in two different mediums.
The organic tail dissolves in the dirt, grime or grease and the ionic head dissolves in water. When the clothes are rinsed or agitated, the Ncert Solution Of Class 10th Hindi Sanchayan Map Ncert Solution Of Class 10th Hindi Sanchayan Map dirt gets pulled out of the clothes in the water by the soap molecule. In this way the soap does its cleaning work on dirty and grimy clothes or hands. The soap molecules actually form a closed structure because of mutual repulsion of the positively charged heads.
This structure is called a micelle. Question 16 Why are carbon and its compounds used as fuels Map Hindi Ncert 10th Sanchayan Solution Of Class Ncert Solution Of Class 10th Hindi Sanchayan Map Ncert Solution Of Class 10th Hindi Sanchayan Map for most applications? Solution: Carbon and its compounds are used as fuels for most of the applications because they burn in air releasing a lot of heat energy. Question 17 Explain the formation of scum when hard water is treated with soap.
Solution: The precipitate form of scum is formed when soap is used for washing clothes. With hard water, a large amount of Ncert Solution Of Class 10th Hindi Sanchayan Map Hindi Class Sanchayan Of 10th Map Solution Ncert Ncert Solution Of Class 10th Hindi Sanchayan Map Ncert Solution Of Class 10th Hindi Sanchayan Map soap is wasted in reacting with the calcium and magnesium ions of hard water to form an insoluble precipitate. The precipitate form formed by the action of hard water on soap, sticks to the clothes being washed and interferes with the cleaning ability of the additional soap.
This makes the cleaning of clothes difficult. Question 18 What change will you observe if you test soap with litmus paper red and blue? Solution: Soap is the salt of a strong base NaOH and a weak acid carboxylic acid , so a solution of soap in water is basic in nature. Being basic, a soap solution turns red litmus paper blue. Question 19 What is hydrogenation?
Solution: It is a class of chemical reactions in which the net result is Ncert Solution Of Class 10th Hindi Sanchayan Map addition of hydrogen H 2 to unsaturated organic compounds such as alkenes, alkynes, etc. Hydrogenation is widely applied to the processing of vegetable oils and fats. Complete hydrogenation converts unsaturated fatty acids to saturated ones. From the above hydrocarbons C 2 H 2 is an alkyne, whereas C 3 H 6 is an alkene. So, C 3 H 6 and C 2 H 2 Ncert Solution Of Class 10th Hindi Sanchayan Map will undergo addition reactions.
Question 21 Give a test that can be used to differentiate chemically between butter and cooking oil. Solution: Bromine water test can be used to differentiate chemically between butter and cooking oil.
Moreover, it is a perfect guide to help you to score good marks in CBSE board examination. With the aim of imbibing skills and hard work among the Ncert Solution Of Class 10th Hindi Sanchayan Map students, the 10th class maths NCERT solutions have been designed. Real Numbers Class 10 has total of four exercises consists of 18 Problems. Other topics included are Fundamental Theorem of Arithmetic, important Ncert Solution Of Class 10th Hindi Sanchayan Map Ncert Solution Of Class 10th Hindi Sanchayan Map properties of positive integers, fraction to decimals and decimals to a fraction.
Polynomials Class 10 has total of four exercises consists of 13 Questions. Problems related to finding polynomials, Properties zeros and Ncert Solution Of Class 10th Hindi Sanchayan Map Ncert Solution Of Class 10th Hindi Sanchayan Map coefficient, long division of polynomials, finding a quadratic polynomial, finding zeros of polynomials are scoring topics. Pair of Linear Equations Class 10 has total of seven exercises consists of 55 Problems.
The Sanchayan Map Solution Hindi 10th Class Ncert Of Ncert Solution Of Class 10th Hindi Sanchayan Map problems will be based on concepts like linear equations in two variables, algebraic methods for solving linear equations, elimination method, cross-multiplication method Time and Work, Age, Boat Stream and equations reducible Ncert Solution Of Class 10th Hindi Sanchayan Map Ncert Solution Of Class 10th Hindi Sanchayan Map Ncert Solution Of Class 10th Hindi Sanchayan Map to a pair of linear equations these answers will give you ease in solving problems related to linear equations.
Quadratic Equations Class 10 has total of four exercises consists of 24 Problems. The Ncert Solution Of Class 10th Hindi Sanchayan Map Questions are related to find roots of quadratic equations and convert world problem into quadratic equations are easily scoring topics in board exams. Arithmetic Progressions Class 10 has total of four exercises consists of 49 Problems.
Triangles Class 10 has total of six exercises consists of 64 Problems. The Questions are based on properties of triangles and 9 important theorems which are important Ncert Solution Of Class 10th Hindi Sanchayan Map in scoring good marks in CBSE Class 10 Exams. Coordinate Geometry Class 10 has total of four exercises consists of 33 Problems.
The Questions related to finding the distance between two points Ncert Solution Of Class 10th Hindi Sanchayan Map using their coordinates, Area of Triangle, Line divided in Ratio Section Formula are important models in class 10 boards. Introduction to Trigonometry Class 10 has total of four exercises consists of 27 Ncert Solution Of Class 10th Hindi Sanchayan Map Problems. The questions based on trigonometric ratios of specific angles, trigonometric identities and trigonometric ratios of complementary angles are the main topics you will learn in this chapter.
Some Applications of Trigonometry Ncert Solution Of Class 10th Hindi Sanchayan Map Ncert Solution Of Class 10th Hindi Sanchayan Map Ncert Solution Of Class 10th Hindi Sanchayan Map Class 10 has one exercise consists of 16 Problems. In this chapter, you will be studying about real life applications of trigonometry and questions are based on the practical applications of trigonometry.
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